اجرای کد در پایتون

درود
میتونید از for, while, do while استفاده کنید اگه منظورتون رو فهمیده باشم
بهتره کدتون رو اینجا بذارید

while True:
code

age khasti mitoni az sleep ham estefade koni

کدم اینه:

print('این کد ۴ عدد اول الگو را گرفته و جمله ان ام را به شما می دهد')
z = int(input('1: '))
q = int(input('2: '))
y = int(input('3: '))
p = int(input('4: '))
n = int(input('your n: '))
x = q-z
w = y-q
m = p-y
k = w-x
h = m-w
v = h-k
a = v/6
b = (k-12*a)/2
c = x-7*a-3*b
d = z-a-b-c
print(n,': ',a*n**3+b*n**2+c*n+d)
print('n: ')
if a != 0 and b != 0 and c != 0 and d != 0:
    print(a,'n^3+',b,'n^2+',c,'n+',d)
if a != 0 and b != 0 and c != 0 and d == 0:
    print(a,'n^3+',b,'n^2+',c,'n')
if a != 0 and b != 0 and c == 0 and d != 0:
    print(a,'n^3+',b,'n^2+',d)
if a != 0 and b == 0 and c != 0 and d != 0:
    print(a,'n^3+',c,'n+',d)
if a == 0 and b != 0 and c != 0 and d != 0:
    print('n^3+',b,'n^2+',c,'n+',d)
if a == 0 and b == 0 and c != 0 and d != 0:
    print(c,'n+',d)
if a != 0 and b != 0 and c == 0 and d == 0:
    print(a,'n^3+',b,'n^2')
if a != 0 and b == 0 and c == 0 and d != 0:
    print(a,'n^3+',d)
if a == 0 and b != 0 and c == 0 and d != 0:
    print('n^3+',b,'n^2+',d)
if a == 0 and b != 0 and c != 0 and d == 0:
    print('n^3+',b,'n^2+',c,'n')
if a != 0 and b == 0 and c != 0 and d == 0:
    print(a,'n^3+',c,'n')
if a == 0 and b == 0 and c == 0 and d != 0:
    print(d)
if a != 0 and b == 0 and c == 0 and d == 0:
    print(a,'n^3')
if a == 0 and b == 0 and c != 0 and d == 0:
    print(c,'n')
if a == 0 and b != 0 and c == 0 and d == 0:
    print(b,'n^2')
if a == 0 and b == 0 and c == 0 and d == 0:
    print()
l = input('آیا میخواهید دوباره امتحان کنید؟')
if l == 'NO':
    Exit()
if l == 'Yes':
    اینجا میخوام دوباره کد تکرار شه

کمکم کنید لطفا.

سلام
کدتون رو درون یک تابع قرار بدید سپس درون یک حلقه مثل while اسم تابع رو بزارید درون یک if و در eles یک exit() بزارید تا از حلقه خارج بشه